The Tens Digit Of Certain Two Digit Number Exceeds The Unit Digits By 3. The Sum Of The Digits Is (1)/(7 (2024)

Mathematics High School

Answers

Answer 1

The two-digit number is 63.

Let's start by representing the two-digit number as "10x + y", where x is the tens digit and y is the ones digit.

From the problem, we know that the tens digit exceeds the ones digit by 3:

x = y + 3

We also know that the sum of the digits is (1/7) of the number:

x + y = (1/7)(10x + y)

Now we can substitute the first equation into the second equation to get:

(y + 3) + y = (1/7)(10(y + 3) + y)

Simplifying this equation gives us:

2y + 3 = (11/7)y + (30/7)

Multiplying both sides by 7 to clear the fraction gives us:

14y + 21 = 11y + 30

Subtracting 11y from both sides gives us:

3y + 21 = 30

Subtracting 21 from both sides gives us:

3y = 9

Dividing both sides by 3 gives us:

y = 3

So the ones digit is 3. We can use the equation x = y + 3 to find the value of the tens digit:

x = 3 + 3 = 6

Therefore, the two-digit number is 63.

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Related Questions

Please help picture attached!

Answers

The value of diagonal DB is 5√2

What is Pythagoras theorem?

Pythagoras theorem states that the sum of the squares on the legs of a right triangle is equal to the square on the hypotenuse.

If a and b are the legs of the triangle and c is the hypotenuse, then

c² = a² + b²

Since the shape is a square, and all the sides of a square are equal, then BC is also 5. The angles in a square are 90°, making triangle BCD a right triangle.

BD = √ 5² + 5²

BD = √25 +25

BD = √50

BD = √25 × √2

BD = 5√2

Therefore the value of length BD is 5√2

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Can anyone solve for y? Thanks!

Answers

Step-by-step explanation:

(4y-6) and 14 are vertical angles this they are equal

[tex]4y - 6 = 14[/tex]

[tex]4y = 20[/tex]

[tex]y = 5[/tex]

Likewise, 5x-5 and 3x+17 are equal

[tex]5x - 5 = 3x + 17[/tex]

[tex]2x = 22[/tex]

[tex]x = 11[/tex]

Please note that the degree measure is not 11 itself, that the value of the x variable,

In fact, if you plug in 11 for x.

The value of the variable will be

50 degrees

In a charity triathlon, Mark ran half the distance and swam a quarter of the distance. When he took a quick break to get a drink of Gatorade, he was just starting to bike the remaining
11
miles. What was the total distance of the race? The total distance of the race was
miles.
2 .In a certain year, there were 84
female officials in Congress, which is comprised of the House of Representatives and the Senate. If there were 58
more female members of the House of Representatives than female senators, find the number of females in each house of Congress. There were
female senators and
female members of the House of Representatives.
Jane and her two friends will rent an apartment for $775
a month, but Jane will pay double what each friend does because she will have her own bedroom. How much will Jane pay a month?
Jane will pay $
per month.

Answers

1. The total distance of the race is 44 miles. 2. There are 13 female senators and 71 female members of the House of Representatives in Congress. Jane will pay $387.50 per month.

1. We are given that Mark ran half the distance and swam a quarter of the distance before starting to bike the remaining 11 miles. Let's represent the total distance of the race as "D."

The distance Mark ran is half of D, so it is D/2.

The distance Mark swam is a quarter of D, so it is D/4.

After Mark's break, he started biking the remaining 11 miles.

Since the total distance of the race is the sum of the distances Mark ran, swam, and biked, we can set up the following equation:

D/2 + D/4 + 11 = D

To solve for D, we can simplify the equation and solve for D:

Multiply the equation by the common denominator, which is 4:

2D + D + 44 = 4D

3D + 44 = 4D

Subtract 3D from both sides:

44 = D

Therefore, the total distance of the race is 44 miles.

2. In the second problem, we are given that there are 84 female officials in Congress, and the number of female members of the House of Representatives is 58 more than the number of female senators. Let's represent the number of female senators as "S" and the number of female members of the House of Representatives as "H."

We are given that the total number of female officials is 84, so we can write the equation:

S + H = 84

We are also given that the number of female members of the House of Representatives is 58 more than the number of female senators:

H = S + 58

To solve for the values of S and H, we can substitute the second equation into the first equation:

S + (S + 58) = 84

2S + 58 = 84

Subtract 58 from both sides:

2S = 26

Divide both sides by 2:

S = 13

Substitute the value of S back into the equation for H:

H = 13 + 58

H = 71

Therefore, there are 13 female senators and 71 female members of the House of Representatives in Congress.

3. In the third problem, Jane and her two friends will rent an apartment for $775 a month, but Jane will pay double what each friend does because she will have her own bedroom. Let's represent the amount each friend pays as "F" and the amount Jane pays as "J."

We are given that Jane will pay double what each friend pays, so we can write the equation:

J = 2F

The total amount they will pay is $775, so we can write the equation:

F + F + J = 775

Substituting the value of J from the first equation into the second equation:

F + F + 2F = 775

4F = 775

Divide both sides by 4:

F = 193.75

Substitute the value of F back into the equation for J:

J = 2(193.75)

J = 387.50

Therefore, Jane will pay $387.50 per month.

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Let A and B denote order-4 matrices, and let P be a point in hom*ogeneous coordinates (a 4x1 matrix with the last component equal to 1). Specify the number of multiplies required to compute

a) (A B) P

b) A (B P)

Note that no multiplies are required to compute the last row of (A B) or the last component of (B P). Explain why it is usually advantageous to combine transformations before applying them (despite the fact that case (a) requires more multiplications.

Answers

Despite the additional multiplications in case (a), it is advantageous to combine transformations before applying them due to benefits such as improved numerical stability, computational efficiency, and code simplicity.

a) To compute (A B) P, we have an order-4 matrix (A B) multiplied by a 4x1 matrix P. Since matrix multiplication involves multiplying the elements of each row of the first matrix with the corresponding elements of each column of the second matrix and summing the products, we have:

Number of multiplies = 4 rows x 4 multiplies per row = 16 multiplies

b) To compute A (B P), we have an order-4 matrix A multiplied by the result of B P, which is also a 4x1 matrix. Since matrix multiplication involves multiplying the elements of each row of the first matrix with the corresponding elements of each column of the second matrix and summing the products, we have:

Number of multiplies = 4 rows x 1 column = 4 multiplies

Despite the fact that case (a) requires more multiplications (16 multiplies) compared to case (b) (4 multiplies), it is usually advantageous to combine transformations before applying them. Here's why:

1. Numerical Stability: Combining transformations can help reduce the accumulation of numerical errors that can occur during matrix operations. Each multiplication operation introduces a certain level of numerical error, so by minimizing the number of multiplications, we can potentially improve the overall accuracy of the computation.

2. Efficiency: Although case (a) requires more multiplications, combining transformations and performing a single multiplication can be more efficient in terms of computation time. Multiplications are typically more computationally expensive than additions or other simple operations, so reducing the number of multiplications can lead to faster execution.

3. Simplification of Code: Combining transformations allows for more compact and simplified code. By representing multiple transformations as a single combined transformation, the code becomes more concise and easier to understand and maintain.

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A retrofitted space-heating system is being considered for a small office building. The system can be purchased and installed for $55,000, and it will save an estimated 200,000 kilowatt-hours (kWh ) of electric power each year over a eight-year period. A kilowatt-hour of electricity costs $0.13, and the company uses a MARR of 18% per year in its economic evaluations of refurbished systems. The market value of the system will be $11,000 at the end of eight years, and additional operating and maintenance expenses are $6,100 per year. Use the benefit-cost method to make a recommendation. Click the icon to view the interest and annuity table for discrete compounding when the MARR is 18% per year. The conventional B-C ratio of the system is . (Round to two decimal places.) This B-C ratio indicates that the project is

Answers

The B-C ratio for the retrofitted space-heating system is 2.52. This indicates that for every dollar invested, the project is expected to generate $2.52 in benefits.

The benefit-cost (B-C) ratio is a measure used to evaluate the economic feasibility of a project. It is calculated by dividing the present value of benefits by the present value of costs.

To calculate the B-C ratio for the retrofitted space-heating system in the small office building, we need to consider the costs and benefits over the eight-year period.

The initial cost of purchasing and installing the system is $55,000. This is a cost that occurs at the beginning of the project.

The annual savings in electric power from the system is 200,000 kWh. With a cost of $0.13 per kWh, the annual savings in electricity costs can be calculated as 200,000 kWh/year * $0.13/kWh = $26,000/year.

The additional operating and maintenance expenses per year are $6,100.

The market value of the system at the end of eight years is $11,000.

To calculate the present value of the benefits and costs, we need to discount them using the company's minimum attractive rate of return (MARR) of 18% per year. The discount factor for each year can be found in the interest and annuity table.

After discounting the annual savings, the market value at the end of eight years, and the annual operating and maintenance expenses, we can calculate the present value of the benefits and costs.

Once we have the present value of benefits and costs, we can calculate the B-C ratio by dividing the present value of benefits by the present value of costs.

Therefore, based on the benefit-cost method, it is recommended to proceed with the retrofitted space-heating system as it has a B-C ratio greater than 1, indicating that the benefits outweigh the costs.

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6. Excel functions to be used for the following methods. a) Straight Line: b) Double Declining Balance: c) Sum of Years Digits: d) Variable Declining Balance:

Answers

a) Straight Line: The Excel function used for the straight-line method is "SLN." b) Double Declining Balance: The Excel function used for the double declining balance method is "DDB." c) Sum of Years Digits: The Excel function used for the sum of years digits method is a combination of "SYD" and other mathematical functions. d) Variable Declining Balance: The Excel function used for the variable declining balance method may vary depending on the specific calculation required.

a) Straight Line: The straight-line method calculates depreciation by dividing the asset's cost by its useful life. In Excel, the "SLN" function is used, which takes three arguments: cost, salvage value, and useful life. The formula is "=SLN(cost, salvage, life)."

b) Double Declining Balance: The double declining balance method applies a constant depreciation rate to the asset's book value. In Excel, the "DDB" function is used, which takes five arguments: cost, salvage value, useful life, period, and factor. The formula is "=DDB(cost, salvage, life, period, [factor])."

c) Sum of Years Digits: The sum of years digits method calculates depreciation by assigning weights to each year based on the asset's useful life. In Excel, the "SYD" function is used, which takes four arguments: cost, salvage value, useful life, and period. The formula is "=SYD(cost, salvage, life, period)."

d) Variable Declining Balance: The variable declining balance method calculates depreciation using a varying depreciation rate based on the asset's expected usage or production levels. The Excel function to be used may depend on the specific calculation or formula required for the variable declining balance method.

Conclusion:

Excel provides specific functions to facilitate the calculations for different depreciation methods. The "SLN" function is used for straight-line depreciation, "DDB" function for double declining balance, and "SYD" function for sum of years digits method. These functions simplify the calculations by taking relevant arguments and producing accurate results. However, for the variable declining balance method, the specific Excel function may vary depending on the formula or calculation required. By utilizing the appropriate Excel functions, depreciation calculations can be performed efficiently and accurately within the chosen depreciation method.

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Evaluate the function at the indicated values. (If an answer is undefined, enter UNDEFINED.) k(x)=−x2−6x+7;
k(0),
k(6),
k(−6),
k(sqrt(6)
k(−x),
k(x^2)
k(a+6)

Answers

The function at the indicated values are

k(0) = 7,

k(6) = -65,

k(-6) = 7,

k(sqrt(6)) = -6(sqrt(6)) + 1,

k(-x) = -x^2 + 6x + 7,

k(x^2) = -x^4 - 6x^2 + 7,

k(a + 6) = -a^2 - 18a - 65.

To evaluate the function k(x) = -x^2 - 6x + 7 at the indicated values, we substitute the given values into the function expression and simplify.

1. k(0):

Substitute x = 0 into the function:

k(0) = -(0)^2 - 6(0) + 7

= -0 - 0 + 7

= 7

Therefore, k(0) = 7.

2. k(6):

Substitute x = 6 into the function:

k(6) = -(6)^2 - 6(6) + 7

= -36 - 36 + 7

= -65

Therefore, k(6) = -65.

3. k(-6):

Substitute x = -6 into the function:

k(-6) = -(-6)^2 - 6(-6) + 7

= -36 + 36 + 7

= 7

Therefore, k(-6) = 7.

4. k(sqrt(6)):

Substitute x = sqrt(6) into the function:

k(sqrt(6)) = -(sqrt(6))^2 - 6(sqrt(6)) + 7

= -6 - 6(sqrt(6)) + 7

= -6(sqrt(6)) + 1

Therefore, k(sqrt(6)) = -6(sqrt(6)) + 1.

5. k(-x):

Substitute x = -x into the function:

k(-x) = -(-x)^2 - 6(-x) + 7

= -x^2 + 6x + 7

Therefore, k(-x) = -x^2 + 6x + 7.

6. k(x^2):

Substitute x = x^2 into the function:

k(x^2) = -(x^2)^2 - 6(x^2) + 7

= -x^4 - 6x^2 + 7

Therefore, k(x^2) = -x^4 - 6x^2 + 7.

7. k(a + 6):

Substitute x = a + 6 into the function:

k(a + 6) = -(a + 6)^2 - 6(a + 6) + 7

= -(a^2 + 12a + 36) - 6a - 36 + 7

= -a^2 - 12a - 36 - 6a - 36 + 7

= -a^2 - 18a - 65

Therefore, k(a + 6) = -a^2 - 18a - 65.

In summary:

k(0) = 7,

k(6) = -65,

k(-6) = 7,

k(sqrt(6)) = -6(sqrt(6)) + 1,

k(-x) = -x^2 + 6x + 7,

k(x^2) = -x^4 - 6x^2 + 7,

k(a + 6) = -a^2 - 18a - 65.

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Bryan charges Php 25.00 for every page of encoding work. In addition, he charges Php 8.00 per page for every printed output. Write a function rule that will provide the amount C for every p encoded page and printed work. How much will Bryan charge for a 33-page encoding and printing work?

Answers

Bryan will charge Php 1089.00 for a 33-page encoding and printing work.

The amount charged by Bryan = Php 25

The amount charged for every page = Php 8

The amount Bryan will charge for a 33-page encoding and printing work = p

Using the function rule for calculating the amount charged by Bryan for encoding and printing work can be written as follows:

C(p) = (25 x p) + (8 x p)

Here the term C(p) represents the amount charged for p pages of encoding and printing work.

Therefore, solving the equation -

C(33) = (25 * 33) + (8 * 33)

= 825 + 264

= 1089

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What does a coefficient of correlation of 0.70 infer?

A. Coefficient of determination is 0.49
B. Coefficient of non-determination is 0.30
C. Almost no correlation because 0.70 is close to 1.0
D. 70% of the variation in one variable is explained by the other

Answers

The coefficient of correlation of 0.70 infer .The meaning of a coefficient of correlation of 0.70, stating that 70% of the variation in one variable is explained by the other.

D. 70% of the variation in one variable is explained by the other.

A coefficient of correlation of 0.70 indicates a strong positive correlation between two variables. It means that there is a strong linear relationship between the variables, and 70% of the variation in one variable can be explained by the other variable.

This implies that the two variables move together in a consistent manner, and there is a high degree of predictability in their relationship.

Option D correctly interprets the meaning of a coefficient of correlation of 0.70, stating that 70% of the variation in one variable is explained by the other.

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In this exercise, we assume that all the functions are asymptotically nonnegative. f=O(g) is defined for asymptotically nonnegative functions f and g (both from N to N ) to mean that there exist positive constants n
0

and c such that: 0≤f(n)≤c⋅g(n) for all n≥n
0

. For each of the following statements either prove the statement if it is true or otherwise provide a counterexample and justify why your counter-example is valid: 1. If f(n)≤g(n), then f(n)=O(g(n)). 2. If f(n)>g(n), then f(n)

=O(g(n)). 3. If f=O(g) then g=O(f). 4. If f=O(g) and g=O(h) then f=O(h). 5. If f=O(g) and g=O(f) and ∀n,f(n)>g(n) then f−g=O(1). 6. If f=O(g),g=O(f), and g(n)>0 for n≥n
0

, then
g
f

=O(1). 7. If f=O(g) and h=O(g) then f=O(h).

Answers

All the statements are False.

The statement is false. For example, if f(n) = n and g(n) = n^2, f(n) ≤ g(n) but f(n) is not asymptotically upper bounded by g(n).The statement is false. For example, if f(n) = n^2 and g(n) = n, f(n) > g(n) but f(n) is not asymptotically lower bounded by g(n).The statement is false. It is possible for f to be asymptotically upper bounded by g, but g is not asymptotically upper bounded by f. For example, if f(n) = n and g(n) = n^2, f=O(g) but g is not O(f).The statement is true. If f=O(g) and g=O(h), then there exist positive constants n0, c1, c2 such that 0 ≤ f(n) ≤ c1 * g(n) and 0 ≤ g(n) ≤ c2 * h(n) for all n ≥ n0. By substituting the second inequality into the first, we get 0 ≤ f(n) ≤ c1 * (c2 * h(n)) = (c1 * c2) * h(n), which shows that f=O(h).The statement is false. Even if f=O(g) and g=O(f), it does not imply that f - g = O(1). For example, if f(n) = 2n and g(n) = n, both f and g satisfy the conditions, but f(n) - g(n) = n, which is not O(1).The statement is false. For example, if f(n) = 1/n and g(n) = 1/n^2, both f and g satisfy the conditions, but g/f = n, which is not O(1).The statement is false. There is no direct relationship between f=O(g) and h=O(g) that guarantees f=O(h). For example, if f(n) = n and g(n) = n^2, both f and g satisfy the conditions, but h(n) = 2n does not satisfy f=O(h).

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If 9(1)/(3) feet of snow fell in 14(2)/(3) days, what was the average snowfall each day?

Answers

As per the given values, the average snowfall each day is around 17.18 feet.

Total snowfall = 9(1)/(3) feet

Number of days = 14(2)/(3) days

Calculating the average snowfall of each day -

Average snowfall = Total snowfall / Number of days

= (9(1)/(3) / (14(2)/(3)

= (9(1)/(3) x (3/(14(2)/(3) )

= (9(1)/(3) x (3/(44/3)

Simplifying the expression to determine the average snowfall -

= (9(1)/(3) feet) x (3/(44/3))

= (28/3 feet) x (3/(44/3))

= (28/3 feet) x (3/1) x (3/(44/3))

= (28/3) x (3/1) x (3/(44/3))

= (28/1) x (3/1) x (3/(44/3))

= 28 x 3 x (3/(44/3))

= 28 x 3 x (9/44)

= 84 x (9/44)

= 756/44

= 17.18

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An astronaut on the moon throws a baseball upward. The astronaut is 6ft,6in. tall, and the initial velocity of the ball is 30ft per sec. The height s of the ball in feet is given by the equation s=−2.7t
2
+30t+6.5, where t is the number of seconds after the ball was thrown. Complete parts a and b. a. After how many seconds is the ball 20ft above the moon's surface? After seconds the ball will be 20ft above the moon's surface. (Round to the nearest hundredth as needed. Use a comma to separate answers as needed.)

Answers

The number of seconds that it will take for the ball to be 20 ft above the moon's surface is: 10.64 seconds

How to solve Quadratic equations of Projectiles?

We want to find after how many seconds (t) is the ball's height (s) 20 feet above the moon's surface.

The height s of the ball in feet is given by the equation:

s(t) = -2.7t² + 30t + 6.5

When s = 20 ft, rearrange the equation to make it equal to 0:

20 = -2.7t² + 30t + 6.5

0 = -2.7t² + 30t - 13.5

Using quadratic formula we have:

x = [-b ± √(b² - 4ac)]/2a

Thus:

t = [-30 ± √(30² - 4(-2.7 * -13.5))]/2(-2.7)

t = 10.64 seconds

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Help please the problem is in the picture I couldn't copy it, sorry!

Answers

Answer:

Step-by-step explanation:

d

6

Marsha serves the volleyball to Rhonda with an upward velocity of 15 (ft)/(s). The ball is 3.5 feet above the ground when she stikes it. How long does Rhonda have to react, before the volleyball hits the ground? Round your answer to two decimal places.

Answers

Rhonda has approximately 0.77 seconds to react before the volleyball hits the ground.

To calculate the time Rhonda has to react, we need to determine how long it takes for the volleyball to reach the ground after Marsha serves it. We can use the equation of motion, which relates the initial velocity (u), time (t), and height (h) of an object in free fall.

The initial velocity of the volleyball is 15 ft/s in the upward direction. Since the ball is 3.5 feet above the ground when struck, we consider the total distance traveled by the ball as the sum of the initial height and the height of the fall.

Using the equation h = ut + (1/2)gt^2, where g is the acceleration due to gravity (approximately 32.2 ft/s^2), we can rearrange the equation to solve for time (t):

3.5 = 15t - (1/2)(32.2)t^2

Simplifying this quadratic equation, we get:

16.1t^2 - 15t + 3.5 = 0

Solving this equation, we find two roots: t ≈ 0.23 s and t ≈ 1.08 s. Since we are interested in the time it takes for the ball to hit the ground, we discard the smaller root (0.23 s) because it corresponds to the time it takes for the ball to reach its maximum height.

Therefore, Rhonda has approximately 1.08 seconds - 0.31 seconds (the time it takes for the ball to reach its initial height) = 0.77 seconds to react before the volleyball hits the ground.

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Section 3 A manufacturer uses a 14\times 34 metal sheet to construct an open box by cutting out squares from each corner. What length square should be cut out to maximize the volume? Round your answer to two decimal places.

Answers

To maximize the volume of the open box, squares with a side length of approximately 9.86 units should be cut out from each corner of the 14x34 metal sheet.

Let's assume that squares with side length x are cut out from each corner of the metal sheet. To form the open box, the remaining sheet is folded to create a rectangular base and four flaps. The length of the rectangular base will be (34 - 2x), and the width will be (14 - 2x). The height of the box will be x.

The volume of the box can be calculated by multiplying the length, width, and height:

V = (34 - 2x)(14 - 2x)(x).

To maximize the volume, we need to find the value of x that maximizes the function V.

Taking the derivative of V with respect to x and setting it equal to zero, we can find the critical points. However, this process involves complicated calculations and is beyond the scope of a simple explanation.

By using optimization techniques or graphing the function, we can determine that the maximum volume occurs when x is approximately 9.86 units. Therefore, squares with a side length of approximately 9.86 units should be cut out from each corner of the 14x34 metal sheet to maximize the volume of the open box.

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Consider the multiplicative group (Z ∗ 80, ·).
(i) Prove that 31 ∈ Z ∗ 80.
(ii) Find the inverse of 31 in the group Z ∗ 80.

Answers

(i) 31 is a member of the multiplicative group Z*80.

(ii) In the group Z*80, 26 is the inverse of 31.

(i) To prove that 31 ∈ Z80, we need to show that 31 is a member of the multiplicative group Z80.

Z80 consists of all the positive integers less than 80 that are coprime (relatively prime) to 80. In other words, the elements of Z80 are the positive integers that do not share any common factors with 80 except for 1.

To show that 31 ∈ Z*80, we need to demonstrate that 31 and 80 are coprime. We can do this by checking if their greatest common divisor (GCD) is 1.

Calculating the GCD of 31 and 80:

80 = 2 * 31 + 18

31 = 1 * 18 + 13

18 = 1 * 13 + 5

13 = 2 * 5 + 3

5 = 1 * 3 + 2

3 = 1 * 2 + 1

2 = 2 * 1 + 0

Since the GCD of 31 and 80 is 1, they are coprime, and thus, 31 ∈ Z*80.

31 is a member of the multiplicative group Z*80.

(ii) To find the inverse of 31 in the group Z*80, we need to find an integer x such that 31 * x ≡ 1 (mod 80).

Using the Extended Euclidean Algorithm, we can find the inverse of 31:

80 = 2 * 31 + 18

31 = 1 * 18 + 13

18 = 1 * 13 + 5

13 = 2 * 5 + 3

5 = 1 * 3 + 2

3 = 1 * 2 + 1

2 = 2 * 1 + 0

Working backward, we can express 1 in terms of the previous remainders:

1 = 3 - 1 * 2

= 2 * 3 - 5

= 2 * 13 - 4 * (18 - 1 * 13)

= 6 * (31 - 1 * 18) - 4 * 18

= 6 * 31 - 10 * 18

= 6 * 31 - 10 * (80 - 2 * 31)

= 26 * 31 - 10 * 80

From this calculation, we can see that the inverse of 31 in Z*80 is 26.

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A pre-paid cell phone company charges $14.8 as a monthly access fee and $0.12 per minute of calling time. Express the monthly cost C in terms of minutes of call time. What will the monthly cost be if you make 414 minutes of calls this month? S

Answers

The monthly cost will be $64.48 if 414 minutes of calls are made this month.

The monthly cost C can be expressed in terms of minutes of call time as follows:

C = 0.12m + 14.8

where m is the number of minutes of call time made in a month.

If 414 minutes of calls are made this month, then the monthly cost will be:

C = 0.12(414) + 14.8

C = 49.68 + 14.8

C = $64.48

Therefore, we can conclude that the monthly cost will be $64.48 if 414 minutes of calls are made this month.

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For each regular expression, give two strings that are in the corresponding language and two strings that are not. 1. a(a+b)

b 2. a

a+λ+b

3. (ab+ba)

Answers

Regular expression is a sequence of characters that define a search pattern. It is mostly used for pattern matching with strings, or string matching. A corresponding language to a regular expression is the language recognized by the regular expression.

Two strings that are in the corresponding language of a regular expression are strings that the regular expression can generate. Two strings that are not in the corresponding language are strings that the regular expression can’t generate.The solution to the problem above is given below:1. a(a+b)*b - This regular expression generates all strings that start with an "a" and end with a "b", and the string has any number of "a"s or "b"s in the middle that can appear in any order.Two strings that are in the corresponding language: ab, aaabbbTwo strings that are not in the corresponding language: ba, abba2. a*a+λ+b* - This regular expression generates all strings that either contain any number of "a"s followed by a "b", or a single "a", or any number of "b"s.

Two strings that are in the corresponding language: aaaab, b, ab

Two strings that are not in the corresponding language: ba, bbab3. (ab+ba)* - This regular expression generates all strings that contain any combination of "ab" or "ba" in any order.

Two strings that are in the corresponding language: aba, ababa

Two strings that are not in the corresponding language: bb, aabba

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Carry the 20×09 adjustments to 20×10 to update the opening balances (page 6). 4.Find 20×10 adjusting entries and other required balances and entries for 20×10 (page 6 ). Adjustment entries in 20X10: Land adjusting entry carried from last year to update the opening balances in 20×10. 1) Adjustment for prior year end's accumulated depreciation, income tax payable and retained earnings. Carried in 20×10 to update 20×09 opening balances. 2) Cepreciation adjusting entry in 20×10. 3) Depreciation adjusting entry in 20×10. Plugged in number to update the Retained Earnings as at December 31, 20×10. \begin{tabular}{|l|l|} \hline Credit adjustment in 20×10 Income Statement from entry (3) above : & $750,000 \\ \hline Debit adjustment in 20×10 Income Statement from entry (4) above: & $225,000 \\ \hline Plugged in number to RE to show the effect of adjustments on net income : & $525,000 \\ \hline \end{tabular} Cash Accumulated depreciation of the equipment sold Cost of the equipment Gain from sale of the equipment MC TRAVEL INC. Balance Sheet December 31, \$

Answers

In 20×10, the adjustment entries include updating opening balances for prior year's accumulated depreciation, income tax payable, and retained earnings. There are also two depreciation adjusting entries. The credit adjustment in the Income Statement is $750,000, and the debit adjustment is $225,000 to update retained earnings.

The adjustment entries for 20×10 include the following:

1) Adjustment for prior year end's accumulated depreciation, income tax payable, and retained earnings carried in 20×10 to update the 20×09 opening balances.

2) Depreciation adjusting entry in 20×10.

3) Depreciation adjusting entry in 20×10 to update the retained earnings as at December 31, 20×10.

The credit adjustment in the 20×10 Income Statement from entry (3) is $750,000, and the debit adjustment from entry (4) is $225,000. A plugged-in number of $525,000 is used to update the retained earnings and show the effect of adjustments on net income.

The adjustment entries in 20×10 are necessary to update the opening balances from the previous year and reflect the changes in various accounts. The first entry adjusts for the accumulated depreciation, income tax payable, and retained earnings from the prior year to update the opening balances in 20×10. The second and third entries involve depreciation adjusting entries for 20×10. These entries account for the depreciation expense incurred during the year and update the retained earnings accordingly.

The credit adjustment in the 20×10 Income Statement from entry (3) represents the increase in income due to the adjustments made. The debit adjustment from entry (4) represents the expenses incurred. A plugged-in number of $525,000 is used to update the retained earnings, reflecting the overall effect of the adjustments on net income.

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x^{2}+13 x+12=0
find value x

Answers

The values of x that satisfy the equation are x = -1 and x = -12.

To solve the quadratic equation x^2 + 13x + 12 = 0, we need to find values of x that satisfy the equation. We can use the quadratic formula:

x = [-b ± sqrt(b^2 - 4ac)] / 2a

where a, b, and c are the coefficients of the quadratic equation.

Substituting the given values, we get:

x = [-(13) ± sqrt((13)^2 - 4(1)(12))] / 2(1)

Simplifying the expression inside the square root, we get:

x = [-13 ± sqrt(169 - 48)] / 2

x = [-13 ± sqrt(121)] / 2

x = [-13 ± 11] / 2

Therefore, the solutions to the equation x^2 + 13x + 12 = 0 are:

x = (-13 + 11) / 2 = -1

or

x = (-13 - 11) / 2 = -12

So the values of x that satisfy the equation are x = -1 and x = -12.

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A chemical company makes two brands of antifreeze. The first brand is 60% gure antifreeze, and the second brand is 80% ourit antireeze. In order to ootain 80 gallons of a mixture that contains 65% pure antifreeze, how many gallons of each brand of antifreeze must be used?

Answers

We need 60 gallons of the first brand of antifreeze and 20 gallons of the second brand of antifreeze to obtain 80 gallons of a mixture that contains 65% pure antifreeze.

Let x be the number of gallons of the first brand of antifreeze, and y be the number of gallons of the second brand of antifreeze used in the mixture.

From the problem, we know that we want to obtain 80 gallons of a mixture that contains 65% pure antifreeze. This means that the amount of pure antifreeze in the mixture is:

0.65 × 80 = 52 gallons

We can set up two equations based on the information given about the percentage of pure antifreeze in each brand of antifreeze:

0.6x + 0.8y = 52 (equation 1)

x + y = 80 (equation 2)

We can solve this system of equations by substitution or elimination. Here, we will use elimination:

Multiplying equation 2 by -0.6, we get:

-0.6x - 0.6y = -48

Adding this to equation 1, we eliminate x:

0.6x + 0.8y = 52 -0.6x - 0.6y = -48

0.2y = 4

Dividing both sides by 0.2, we get:

y = 20

Substituting this value into equation 2, we get:

x + 20 = 80

x = 60

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The mean of 11 numbers is 9 . On the numbers, 19 , is deleted. What is the mean of the remaining numbers?

Answers

The mean of the numbers after deleting 19 is 8.

Given that set of 11 numbers has mean 9.

To calculate the mean of the numbers after deleting 19, adjust the sum of the numbers and find the new mean.

Sum of the 11 numbers = Mean × Total Count

Sum of the 11 numbers = 9 × 11

Sum of the 11 numbers = 99

After delete 19 from the set of 11 numbers, subtract 19 from the sum:

Sum of 10 numbers = Sum - 19

Sum of 10 numbers = 99 - 19

Sum of 10 numbers = 80

New Mean = Sum of 10 numbers / Remaining Count

New Mean = 80 / 10

New Mean = 8

Hence, the mean of the numbers after deleting 19 is 8.

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Suppose that the functions h and g are defined as follows.
h(x)=−5+4x
2

g(x)=6−2x

(a) Find (
g
h

)(−2) (b) Find all values that are NOT in the domain of
g
h

. If there is more than one value, separate them with commas. (a) (
g
h

)(−2)=

Answers

a) The output value of (g∘h)(-2) is 32.

b. A value that is not in the domain of (g∘h)(x) is 2.

How to determine the corresponding composite function function?

In this scenario, we would determine the corresponding composite function of h(x) and g(x) under the given mathematical operations (multiplication) in simplified form as follows;

(g∘h)(x) = 6 - 2(-5 + 4x)

(g∘h)(x) = 6 + 10 - 8x

(g∘h)(x) = 16 - 8x

When x = -2, we have:

(g∘h)(-2) = 16 - 8(-2)

(g∘h)(-2) = 16 + 16

(g∘h)(-2) = 32.

Part b.

For the value that is not in the domain of (g∘h)(x), we have the following:

(g∘h)(x) = 16 - 8x

0 = 16 - 8x

8x = 16

x = 16/8

x = 2.

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4) Let f(z)=u+iv be analytic. If u is a harmonic conjugate of v and v is a harmonic conjugate of u then a) u is constant, v is non-constant b) v is constant, u is non-constant c) Both u and v are non-constants d) f(z) is constant e) NOTA

Answers

The correct answer is (d) f(z) is constant, as both u and v being harmonic conjugates of each other implies that f(z) is a constant function.

The idea of harmonic conjugates and analytical functions is the focus of the given problem. Let's look at the options to figure out the right answer:

a) While v is not constant, u is constant: The real part of the analytical function f(z) is a harmonic function if u is a harmonic conjugate of v. It follows that the imaginary part of f(z) is also a harmonic function if v is also a harmonic conjugate of u. Since f(z)'s real and imaginary parts are harmonic functions, u and v are both constants in this case.

b) While u is not constant, v is constant: Similar to option (a), the assumption that the imaginary part of f(z) is a harmonic function is true if v is a harmonic conjugate of u. However, the real part of f(z) is also a harmonic function if u is also a harmonic conjugate of v. As a result, u and v are both constants.

c) v and u are both non-constants: Options (a) and (b) explain that both u and v must be constants if they are harmonic conjugates of one another. Consequently, this choice is incorrect.

d) The constant f(z) is The real and imaginary parts of f(z) are harmonic functions if u and v are harmonic conjugates of one another. Since u and v are both constants in this scenario, f(z) must also be constant.

e) NOTA: This selection does not provide a specific response and implies "None of the above." It does not assist in making the best decision.

Given that both u and v are harmonic conjugates of one another, which implies that f(z) is a constant function, the correct response is (d) f(z) is constant.

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Describe how the given function can be obtained from one of the basic graphs. Then graph the function. g(x)=−(x−8) ^
3
Select the correct choice below and fill in the answer box to complete your choice. A. Start with the graph of f(x)=□. Shift it left 8 units and then reflect it across the x-axis. B. Start with the graph of f(x)=□. Shift it right 8 units and then reflect it across the x-axis. C. Start with the graph of f(x)=. Shift it left 8 units and then reflect it across the y-axis. D. Start with the graph of f(x)= Shift it right 8 units and then reflect it across the y-axis.

Answers

The correct option is B, B. Start with the graph of f(x)= (x)³. Shift it right 8 units and then reflect it across the x-axis.

How to get the transformed function?

We start with the parent cubic function:

f(x) = (x)³

We can start by applying a translation of 8 units to the right, then we will get the function:

g(x) = f(x - 8) = (x - 8)³

Finally, we can apply a reflection over the x-axis, that adds a factor of -1, then:

g(x) = -f(x - 8) = - (x - 8)³

That is the transformed function.

Then the correct option is B.

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Find the area of the parallelogram with vertices at \( (-3,-5),(3,-1),(2,-5) \), and \( (8,-1) \)

Answers

To find the area of the parallelogram with the given vertices, we can use the formula for the area of a parallelogram. the area of the parallelogram is 20 square units.

Let's label the vertices as A(-3, -5), B(3, -1), C(2, -5), and D(8, -1). To calculate the area, we first need to determine the vectors formed by the vertices. We can choose vectors AB and AD.

Vector AB = (x_B - x_A, y_B - y_A) = (3 - (-3), -1 - (-5)) = (6, 4)

Vector AD = (x_D - x_A, y_D - y_A) = (8 - (-3), -1 - (-5)) = (11, 4)

Next, we calculate the cross product of these vectors. The cross product is given by the formula: cross product = (AB)_x * (AD)_y - (AB)_y * (AD)_x.

(AB)_x = 6, (AB)_y = 4

(AD)_x = 11, (AD)_y = 4

Cross product = (6 * 4) - (4 * 11) = 24 - 44 = -2

Finally, we take the absolute value of the cross product to obtain the area:

Area = | -20 | = 20 square units.

Therefore, the area of the parallelogram is 20 square units.

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Compute the objective function value for the following problem: Min 273X+ 299Y subject to : 2X>=0;21X+23Y=483;X+Y>=0 a. infeasible b. 0 c. 6279 d. 433.82608 e. unbounded

Answers

The objective function value for this problem is 6279. The correct answer is c. 6279.

To compute the objective function value for the given problem, we need to find the values of X and Y that satisfy the constraints and minimize the objective function.

The constraints are as follows:

2X ≥ 0

21X + 23Y = 483

X + Y ≥ 0

Let's solve the second constraint for Y:

21X + 23Y = 483

23Y = 483 - 21X

Y = (483 - 21X) / 23

We can substitute this value of Y in the third constraint to eliminate Y:

X + Y ≥ 0

X + (483 - 21X) / 23 ≥ 0

Simplifying the inequality:

23X + 483 - 21X ≥ 0

2X + 483 ≥ 0

2X ≥ -483

X ≥ -241.5

Since X must be greater than or equal to zero according to the first constraint, the feasible range for X is X ≥ 0.

Now, substituting the feasible values of X in the objective function:

273X + 299Y = 273(0) + 299Y = 299Y

To minimize this expression, we need to find the minimum value of Y.

Using the second constraint:

21X + 23Y = 483

21(0) + 23Y = 483

23Y = 483

Y = 21

Substituting this value of Y in the objective function:

273X + 299Y = 273(0) + 299(21) = 0 + 6279 = 6279

Therefore, the objective function value for this problem is 6279. The correct answer is c. 6279.

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Find the constants m and b in the linear function f(x)=mx+b so that f(7)=9 and the straight line represented by f has slope −3.
m=
b=

Answers

To find the constants m and b in the linear function f(x) = mx + b, we can use the given conditions f(7) = 9 and a slope of -3.

The value of f(7) represents the y-coordinate of the point on the line when x = 7. So, substituting x = 7 into the equation, we get 9 = 7m + b.

The slope of a linear function is given by the coefficient of x, which in this case is -3. So, we have m = -3.

Now, we can substitute the value of m into the equation obtained from f(7). We get 9 = 7(-3) + b, which simplifies to 9 = -21 + b.

Solving for b, we find b = 30.

Therefore, the constants for the linear function f(x) = mx + b that satisfy the given conditions are m = -3 and b = 30.

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The water equivalent ratio for dry powdery snow is 30:1. How much water is in 45 inches of dry powdery snow?
a. 0.67 inches
b. 1.5 inches
c. 45 inches
d. 1,350 inches

Answers

The correct answer is option d.1350 inches.There are 1350 inches of water in 45 inches of dry powdery snow.

The water equivalent ratio for dry powdery snow is 30:1, meaning that for every inch of snow, there is an equivalent of 30 inches of water. To determine the amount of water in 45 inches of dry powdery snow, we need to multiply 45 by the water equivalent ratio of 30:1.

45 inches of snow multiplied by the water equivalent ratio of 30:1 gives us:

45 inches x 30 inches of water per inch of snow = 1350 inches of water.

Therefore, there are 1350 inches of water in 45 inches of dry powdery snow.

The correct answer is option d. 1,350 inches.

In summary, when given the water equivalent ratio for dry powdery snow and the depth of snow, we can calculate the equivalent amount of water by multiplying the depth of snow by the water equivalent ratio. In this case, multiplying 45 inches by the water equivalent ratio of 30:1 gives us 1350 inches of water.

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Twenty percent of computer parts produced by a certain supplier
are defective. What is the probability that a sample of 10 parts
contains 4 defective ones?

Answers

The probability that a sample of 10 parts contains 4 defective ones, given that 20% of the computer parts produced are defective, is approximately 0.21.

To calculate the probability, we can use the binomial probability formula. Let's denote the probability of a part being defective as p = 0.2 and the number of trials as n = 10.

The formula for calculating the probability of getting exactly k successes in n trials is:

P(X = k) = C(n, k) * p^k * (1 - p)^(n - k)

where C(n, k) represents the number of combinations of n items taken k at a time.

Plugging in the values for our case, we have:

P(X = 4) = C(10, 4) * 0.2^4 * (1 - 0.2)^(10 - 4)

Calculating the values:

C(10, 4) = 10! / (4! * (10 - 4)!) = 210

0.2^4 ≈ 0.0016

(1 - 0.2)^(10 - 4) ≈ 0.1074

P(X = 4) = 210 * 0.0016 * 0.1074 ≈ 0.0340

Rounding to two decimal places, the probability is approximately 0.03.

The probability that a sample of 10 computer parts contains 4 defective ones, given that 20% of the parts produced are defective, is approximately 0.03 or 3.40% when rounded to two decimal places.

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The Tens Digit Of Certain Two Digit Number Exceeds The Unit Digits By 3. The Sum Of The Digits Is (1)/(7 (2024)

FAQs

What number consists of 2 digits of which the tens digit exceeds the units digit? ›

As given, a number consists of two digits in which the tens digit exceeds the units digit by 6 and the number itself is equal to ten times the sum of digits. Hence, the given number is 60.

How many 2 digit numbers are there where the tens digit is larger than the units digit? ›

Here are the numbers that satisfy the conditions. 90, 91, 92, 93, 94, 95, 96, 97, 98, Hence the total is 1+2+3+4+5+6+7+8+9=45 numbers.

What is a number of two digits has 3 for its unit digit and the sum of digits is 1 7 of the number itself? ›

As, unit digit = 3 , Suppose ten digit =X, then a/c to situation... (10x+3)1/7 =x+3... solving this equation we get X= 6... hence two digit number is 63.

What digit at the tens place of a two digit number is three times the digit at the ones place? ›

Hence, the number is 62. Q. The digit at the tens place of a two digit number is three times the digit at the units place.

What is the tens digit of a two digit number? ›

For a two digit number, the digit at tens place is twice the digit at the units place.

What is the unit digit of a two digit number is 3 times its tens digit? ›

Given that unit digit of a two digit number is 3 times its ten digit. Given that unit digit is 6. Ten digit is 2. Hence, the number is 26.

Where is the tens place in a 2-digit number? ›

The place digit is the right-sided digit of a two-digit number. 46 stands for 4 tens and 6 ones. The left-side digit, 4 in 46, is the tens digit. The right-side digit, 6 in 46, is the one digit.

What is tens digit and unit digit? ›

"Unity" means one, so the units digit is the digit in the one's column. Eg. for the number 138, the 1 is in the hundreds column, the 3 is in the tens column and the 8 is in the one's column, so 8 is the unit digit of 138.

What is the number in a 2 digit number the units digit is four times the tens digit and the sum of the digits is 10? ›

Hence, the number is 28. Ans. Q. In a two-digit number the units digit is four times the tens digit and the sum of the digits is 10.

What are the units digits of a two-digit number? ›

In a two-digit number, the units digit is twice the tens digit. If 9 is added to the number, the digits interchange their places.

What is the total number of three digit three digit numbers with unit digit 7 and divisible by 11? ›

So, the numbers that were divisible by 11 with unit digit 7 is 187, 297, 407, 517, 627, 737, 847 and 957 which is a total of 8. We have found that there are 8 three-digit numbers with unit digit 7 and divisible by 11.

How many 2 digit numbers have tens digit smaller than the unit digit? ›

30 , 31 and 32 are such numbers, but not 33, 34 and so on … there are 3 such numbers.

What number consists of two digits in which the tens digit exceeds the units digit by 6? ›

The number is 60. Q. A number consists of two digits in which the tens digit exceeds the units digit by 6. The number itself is equal to ten times the sum of digits.

Which digits are in tens place? ›

The tens place is always located two digits to the left of the decimal point. Remember, even whole numbers can be written with a decimal point. For example, 34 can be written as 34.0, which means that 3 is in the tens place. This 3 represents 3 groups of ten.

What is a two digit number where tens digit is greater than ones digit? ›

so there are total three numbers that can be formed using the conditions given in the question and that are 31, 62 and 93.

What is the two digit if it is known that its unit digit exceeds its tens digit by 2? ›

In a two-digit number, if it is known that its unit's digit exceeds its ten's digit by 2 and that the product of the given number and the sum of its digit is equal to 144, then the number is. 24.

Which digit tells the number of tens for a two digit number? ›

Understanding Tens Digit & One's Digit:

The place digit is the right-sided digit of a two-digit number. 46 stands for 4 tens and 6 ones. The left-side digit, 4 in 46, is the tens digit. The right-side digit, 6 in 46, is the one digit.

Which two digit number is such that the unit digit exceeds the tens digit by 5? ›

Hence the correct answer is 72.

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